SOLUTION: Given a polynomial and one or more of its roots, find the remaining roots: y = x3 - 4x2 - 9x + 36; root = -3

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Given a polynomial and one or more of its roots, find the remaining roots: y = x3 - 4x2 - 9x + 36; root = -3       Log On


   

Question 1168331: Given a polynomial and one or more of its roots, find the remaining roots:
y = x3 - 4x2 - 9x + 36; root = -3

Found 2 solutions by Boreal, dkppathak:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
synthetic division using
-3/1== -4===-9===36
==1===-7===12===0
so the remainder is x^2-7x+12, which factors into (x-4)(x-3), and the roots are 3 and 4.
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3-4x%5E2-9x%2B36%29

Answer by dkppathak(439) About Me  (Show Source):
You can put this solution on YOUR website!
Given a polynomial and one or more of its roots, find the remaining roots:
y = x3 - 4x2 - 9x + 36; root = -3
solution
x=-3 one root than x+3 is factor
x^2(x+3)-7x(x+3)+12(x+3)
(x+3)(x^2-7x+12)
(x+3)(x-4)(x-3)
x-4=0
x=4 similarly x=3
roots of polynomial 3,4,-3