SOLUTION: a satellite dish has a shaped of a paraboloid. If the receiver of the satellite dish is placed at the focus 2.53 ft from the vertex, write an equation for the cross-section of the

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: a satellite dish has a shaped of a paraboloid. If the receiver of the satellite dish is placed at the focus 2.53 ft from the vertex, write an equation for the cross-section of the       Log On


   



Question 1165727: a satellite dish has a shaped of a paraboloid. If the receiver of the satellite dish is placed at the focus 2.53 ft from the vertex, write an equation for the cross-section of the satellite dish. Assume that the focus is on the positive x-axis and its vertex at the origin.
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
a satellite dish has a highlight%28cross%28shaped%29%29 shape of a paraboloid. If the receiver of the satellite dish
is placed at the focus 2.53 ft from the vertex, write an equation for the cross-section
of the satellite dish. Assume that the focus is on the positive x-axis and its vertex at the origin.
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        It is a standard problem of this kind. The feature is
        that in this problem the symmetry line is parallel to x-axis,
        while usually in such problems the symmetry line is parallel to y-axis.
        So, I will adapt a standard solution to this case.


For solving such problems, write an equation of the parabola in the cross-section
in the form

    x = %281%2F%284p%29%29%2Ay%5E2.    (1)


The advantage of writing in this form is the fact that then "p"
is the distance from the parabola vertex to its focus.


In this problem, the value of p is given: it is 2.53 ft.


So, we substitute this value into equation (1), and we get

    x = %281%2F%284%2A2.53%29%29%2Ay%5E2.


It gives the equation of the parabolic section 

    x = %281%2F10.12%29%2Ay%5E2,  or  x = 0.098814229%2Ay%5E2.    ANSWER

Solved.