SOLUTION: what is the root of this quadratic equation; 1. x² - x = 0 2. 3x² = - 6x 3. x² - 4x - 5 = 0 4. 4x² + 1 = 2x² + 17 5. 3x² -6x - 7 = 2x²

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: what is the root of this quadratic equation; 1. x² - x = 0 2. 3x² = - 6x 3. x² - 4x - 5 = 0 4. 4x² + 1 = 2x² + 17 5. 3x² -6x - 7 = 2x²       Log On


   

Question 1164079: what is the root of this quadratic equation;
1. x² - x = 0
2. 3x² = - 6x
3. x² - 4x - 5 = 0
4. 4x² + 1 = 2x² + 17
5. 3x² -6x - 7 = 2x²
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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what is the root of this quadratic equation;
1. x² - x = 0
2. 3x² = - 6x
3. x² - 4x - 5 = 0
4. 4x² + 1 = 2x² + 17
5. 3x² -6x - 7 = 2x²
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Just doing #5:
3x%5E2-6x-7=2x%5E2
3x%5E2-2x%5E2-6x-7=0
x%5E2-6x-7=0
easily factorable to
%28x-7%29%28x%2B1%29=0
roots obviously 7 and -1.