SOLUTION: A positive real number is 4 less than another. When 8 times the larger is added to the square of the smaller, the result is 96. Find the numbers.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A positive real number is 4 less than another. When 8 times the larger is added to the square of the smaller, the result is 96. Find the numbers.      Log On


   

Question 1163436: A positive real number is 4 less than another. When 8 times the larger is added to the square of the smaller, the result is 96. Find the numbers.
Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


A positive real number is 4 less than another.

Let the two numbers be x and x-4.

When 8 times the larger is added to the square of the smaller, the result is 96.

%28x-4%29%5E2%2B8x+=+96

Find the numbers.

x%5E2-8x%2B16%2B8x+=+96
x%5E2%2B16+=+96
x%5E2+=+80
x+=+sqrt%2880%29+=+4%2Asqrt%285%29

Note the problem says x is positive, so we ignore the negative value.

ANSWERS: The two numbers are 4%2Asqrt%285%29 and 4%2Asqrt%285%29-4

CHECK: