SOLUTION: I do not understand these problems...
An arrow is shot upward at an initial velocity of 40 meters per second. Use the function: h=40t-5t^2 to answer the following questions:
Question 1159348: I do not understand these problems...
An arrow is shot upward at an initial velocity of 40 meters per second. Use the function: h=40t-5t^2 to answer the following questions:
1).what is the height of the arrow in meters after 5 seconds? Solve algebraically. Show Work.
2). After how many seconds will the arrow be 30 meters high? Use the quadratic formula. Show work.
3). when will the arrow be back on the ground? solve algebraically using factoring. Show work.
Thank you for your help Found 3 solutions by Boreal, MathLover1, ikleyn:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Draw a parabola to show the path of the arrow.
The equation is height=-5t^2+40t, the -5 is acceleration of gravity (-4.9 more accurately) and the 40 is the speed of the arrow in m/sec. The units are (m/sec^2)(sec^2) or meters and (m/sec)*sec or meters.
t is the number of seconds
h(5)=-5(25)+40(5)=75 meters high
the arrow is 30 meters high twice, going up and coming down
30=-5t^2+40t
rewrite to make t^2 term positive. It's easier that way.
5t^2-40t+30=0
divide by 5 to simplify it
t^2-8t+6=0
quadratic formula
t=(1/2)(8+/8+/-sqrt(64-24) or (1/2)* 8 +/- sqrt (40) which is 2 sqrt(10)
t=4+/- sqrt (10) multiplying it by the 1/2
This is at t=7.16 seconds and 0.84 seconds. You can make those to more decimal places if you wish and show that they will both give 30 m when put into the equation.
it hits the ground when H(t)=0
-5t^2+40t=0
5t^2=40t
t^2=8t
t=8 seconds
If you substitute 8 into the equation, it equals 0.
1).what is the height of the arrow in meters after seconds?
........if seconds
meters high
2). After how many seconds will the arrow be meters high?
........if ......simplify, divide by .......use quadratic formula
.........simplify
-> solutions:
-> seconds
-> seconds
so, it will ritch height of meters in seconds and second time (on its way back) seconds
3). when will the arrow be back on the ground?
the arrow be back on the ground when
->->when ...this is start position
->->when -> it will take seconds for the arrow to be back on the ground
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