SOLUTION: In July, Mr Chauhan again changed 1140 Rupees into Marks. The rate of exchange was then (x+1) Rupees = 1 Mark. a) Write down an expression, in terms of x, for the number of Marks

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: In July, Mr Chauhan again changed 1140 Rupees into Marks. The rate of exchange was then (x+1) Rupees = 1 Mark. a) Write down an expression, in terms of x, for the number of Marks      Log On


   

Question 1157831: In July, Mr Chauhan again changed 1140 Rupees into Marks. The rate of exchange was then (x+1) Rupees = 1 Mark.
a) Write down an expression, in terms of x, for the number of Marks he received this time.
b) Given that he received 3 Marks less in July than he received in May, form an equation in x and show that it reduces to x^2+x-380=0.
c) Solve this equation to find the rate of exchange in May 1994.
Answer by Shin123(626) About Me  (Show Source):
You can put this solution on YOUR website!
a) (x+1) Rupees = 1 Mark. Multiply both sides by 1140%2F%28x%2B1%29 to get 1140 Rupees = 1140/(x+1) Marks