SOLUTION: If r and a represent the solutions of the equation (3k + 14) * k = 5 and r > s, what is the value of the difference of r - s?

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Question 1151314: If r and a represent the solutions of the equation (3k + 14) * k = 5 and r > s, what is the value of the difference of r - s?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.

Do you know the quadratic formula ?


It has the form       r,s = %28-b+%2B-+something%29%2F%282a%29,

where b is the coefficient at "k" and "a" is the coefficient at "k^2" in the standard form equation.


When you subtract  r-s, you will get this "something", divided by "a".


Now, the standard form of the equation is


    3k^2 + 14k - 5 = 0.


The "something" is the square root of the discriminant  sqrt%28b%5E2+-+4ac%29 = sqrt%2814%5E2+-+4%2A3%2A%28-5%29%29 = sqrt%28256%29 = 16.


The "a" is 3.


Therefore, the answer is  16%2F3.


ANSWER.  The difference r - s = 16%2F3.

Solved.

---------------

On quadratic formula, see the lessons
    - Introduction into Quadratic Equations
    - PROOF of quadratic formula by completing the square
in this site.


Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


If r and cross%28a%29 s represent the solutions of the equation (3k + 14) * k = 5 and r > s, what is the value of the difference of r - s?
%283k+%2B+14%29+%2A+k+=+5

3k%5E2%2B14k+=+5

3k%5E2%2B14k-5=0

%283k-1%29%28k%2B5%29+=+0

k+=+1%2F3 or k+=+-5

So r = 1/3 and s = -5; and the difference r-s is 1/3+5 = 16/3.

Alternatively, we can find the value of r-s without factoring.

The solutions to the equation

ax%5E2%2Bbx%2Bc=0

are

%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29 and %28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29

The difference between the two roots is then

2%28sqrt%28b%5E2-4ac%29%29%2F%282a%29+=+%28sqrt%28b%5E2-4ac%29%29%2Fa

For the quadratic in this problem that difference is

sqrt%2814%5E2-4%2A3%2A%28-5%29%29%2F3=+sqrt%28256%29%2F3+=+16%2F3