SOLUTION: A wire of length 200 is cut into two parts and each part is bent to form a square.if the area of the larger square is 9 times that of smaller square,find the perimeter of the large

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A wire of length 200 is cut into two parts and each part is bent to form a square.if the area of the larger square is 9 times that of smaller square,find the perimeter of the large      Log On


   

Question 1150938: A wire of length 200 is cut into two parts and each part is bent to form a square.if the area of the larger square is 9 times that of smaller square,find the perimeter of the larger square.
Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.

Since the ratio of the areas is 9:1, it means that the ratio of linear dimensions is 3:1,  where 3 = sqrt%289%29.


So, the perimeter of the larger square is 3 times the perimeter of the smaller square,

and the sum of the perimeters is 200 units.



Hence, the perimeter of the smaller square is 50 units, while the perimeter of the larger square is 150 inits.    ANSWER

Solved.