SOLUTION: A woman is four times older than her daughter,6 years ago the product of their ages was 136.Find their present ages

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A woman is four times older than her daughter,6 years ago the product of their ages was 136.Find their present ages       Log On


   



Question 1150843: A woman is four times older than her daughter,6 years ago the product of their ages was 136.Find their present ages
Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Present age of the woman, 5d
Daughter age, d
%285d-6%29%28d-6%29=136
Solve for d.

Possible mistake in problem description.
d not whole number.

If description said "woman is four times the age of her daughter", then d=10.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A woman is four times older than her daughter,6 years ago the product of their ages was 136.Find their present ages
================
If someone doesn't know the difference between "four times older" and "four times as old" they should not be writing math problems.
Or anything else.
===================
If someone says "four times smaller" or "four times closer" hit them on the head.