SOLUTION: A rectangle is drawn so the width is 9 inches longer than the height. If the rectangle's diagonal measurement is 45 inches, find the height. Give your answer rounded to 1 decima

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A rectangle is drawn so the width is 9 inches longer than the height. If the rectangle's diagonal measurement is 45 inches, find the height. Give your answer rounded to 1 decima      Log On


   

Question 1147580: A rectangle is drawn so the width is 9 inches longer than the height. If the rectangle's diagonal measurement is 45 inches, find the height.
Give your answer rounded to 1 decimal place.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangle is drawn so the width is 9 inches longer than the height. If the rectangle's diagonal measurement is 45 inches, find the height.
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w = h + 9
w^2 + h^2 = 45^2
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Give your answer rounded to 1 decimal place.
Couldn't you do the rounding?