SOLUTION: How to write quadratic function if vertex is (-3,-3) and y intercept is (0,6)

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Question 1146276: How to write quadratic function if vertex is (-3,-3) and y intercept is (0,6)
Found 3 solutions by ankor@dixie-net.com, josgarithmetic, MathTherapy:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website!
How to write quadratic function if vertex is (-3,-3) and y intercept is (0,6)
:
Using this form, ax^2 + bx + c = y
x=-3, c=6, y=-3, Assume a=1
9(1) - 3b + 6 = -3
find b
-3b + 15 = -3
=3b = -3 -15
-3b = -18
b = -18/-3
b = 6
The equation: y = x^2 + 6x + 6
Graphically

Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website!
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quadratic function if vertex is (-3,-3) and y intercept is (0,6)
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substitute given point:

-
-------------you could multiply and simplify if you want to.

Answer by MathTherapy(10552)   (Show Source):
You can put this solution on YOUR website!

How to write quadratic function if vertex is (-3,-3) and y intercept is (0,6)

Equation of a parabola in vertex-form : , with:
(h, k) being the coordinates of the vertex of the parabola
(x, y) being a point on the parabola
"a" being the width and location of the parabola
------ Substituting (- 3, - 3) for (h, k) and (0, 6) for (x, y) in order to determine the value of "a."
6 = 9a - 3
6 + 3 = 9a
9 = 9a

Equation of parabola in vertex-form: