SOLUTION: hey,
could answer this question for me.
find the quadratic relation in vertex form that has zeros -3 and 5 and passes through (3,6).
i found the x-symmetry which is -3+5= 2/2
Question 113832: hey,
could answer this question for me.
find the quadratic relation in vertex form that has zeros -3 and 5 and passes through (3,6).
i found the x-symmetry which is -3+5= 2/2 = 1
Therefore x=1
but i did get how to find the y value
could u please solve it to me and send it back.
i will be waiting.
thank you, Found 2 solutions by stanbon, edjones:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find the quadratic relation in vertex form that has zeros -3 and 5 and passes through (3,6).
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f(x) = a(x+3)(x-5)
f(3)=6
Therefore:
f(3) = a(3+3)(3-5)=6
a*6*-2=6
-12a = 6
a = -1/2
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EQUATION:
f(x) = (-1/2)(x+3)(x-5)
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This quadratic has zeros at x=-3,and x=5, and passes thru (3,6)
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Cheers,
Stan H.
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