SOLUTION: Find an equation of the line satisfying the given conditions. Passing through (4,−3) and perpendicular to the line 5y= -4x/7 + 5

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find an equation of the line satisfying the given conditions. Passing through (4,−3) and perpendicular to the line 5y= -4x/7 + 5      Log On


   

Question 1134563: Find an equation of the line satisfying the given conditions.
Passing through (4,−3) and perpendicular to the line 5y= -4x/7 + 5
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+5y+=+-4x%2F7+%2B+5+
+y+=+%28-4%2F35%29%2Ax+%2B+1+
Slope, +m+=+-4%2F35+
Any line perpendicular to this line has
slope +-1%2Fm+=+35%2F4+
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use the general point-slope formula
+%28+y+-%28-3%29+%29+%2F+%28+x+-+4+%29+=+35%2F4+
Multiply both sides by +4%2A%28+x+-+4+%29+
+4%2A%28+y+%2B+3+%29+=+35%2A%28+x+-+4+%29+
+4y+%2B+12+=+35x+-+140+
+4y+=+35x+-+152+
+y+=+%2835%2F4%29%2Ax+-+38+
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Here's a plot of the 2 lines

Looks OK