SOLUTION: Can someone please help? The cost function for a certain company is C = 40x + 500 and the revenue is given by R = 100x − 0.5x2. Recall that profit is revenue minus cost.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Can someone please help? The cost function for a certain company is C = 40x + 500 and the revenue is given by R = 100x − 0.5x2. Recall that profit is revenue minus cost.       Log On


   

Question 1134246: Can someone please help?
The cost function for a certain company is C = 40x + 500
and the revenue is given by R = 100x − 0.5x2.
Recall that profit is revenue minus cost. Set up a quadratic equation and find two values of x (production level) that will create a profit of $500.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
R-C=100x-0.5x^2-40x-500
so -0.5x^2+60x-500=0
solve for -0.5x^2+60x-500=500 or -0.5x^2+60x-1000=0 or x^2-120x+2000=0, multiplying the previous by -2.
(x-100)(x-20)=0, x=20 and 100
graph%28300%2C300%2C-30%2C300%2C-1000%2C2000%2C-0.5x%5E2%2B60x-500%2C500%29