Question 1130883: The graph of a quadratic function has x-intercepts -10 and 2. Write a quadratic equation in standard form that has these roots.
Thank you
Answer by ikleyn(52778) (Show Source):
You can put this solution on YOUR website! .
f(x) = a*(x-(-10))*(x-2) = a*(x+10)*(x-2) = a*(x^2 +8x - 20) = ax^2 + 8ax -20a, (*)
where a is an arbitrary real number.
It is the most general standard form of such a function.
If you want to have an equation, equate (*) to zero:
ax^2 + 8ax - 20a = 0.
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