SOLUTION: What are the roots of the equation x^2-16x+73=0x 2 −16x+73=0 in simplest a+bia+bi form?

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Question 1128710: What are the roots of the equation x^2-16x+73=0x
2
−16x+73=0 in simplest a+bia+bi form?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E2-16x%2B73=0 .........use quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+......in your case a=1,b=-16, and c=73
x+=+%28-%28-16%29+%2B-+sqrt%28+%28-16%29+%5E2-4%2A1%2A73+%29%29%2F%282%2A1%29+
x+=+%2816+%2B-+sqrt%28+256-292+%29%29%2F2+
x+=+%2816+%2B-+sqrt%28-36%29%29%2F2+
x+=+%2816+%2B-+sqrt%28-1%2A6%5E2%29%29%2F2+
x+=+%2816+%2B-+sqrt%28-1%29%2Asqrt%286%5E2%29%29%2F2+
x+=+%2816+%2B-+6i%29%2F2+
x+=+%2816%2F2+%2B-+6i%2F2%29+
x+=+%288+%2B-+3i%29+
solutions:
x+=+8+%2B+3i+
x+=+8+-+3i+