SOLUTION: Hi! I have a problem that my professor wants me to solve by completing the square. The problem says:
A train travels 300 miles at a uniform speed. If its speed had been 15 mile
Question 1128578: Hi! I have a problem that my professor wants me to solve by completing the square. The problem says:
A train travels 300 miles at a uniform speed. If its speed had been 15 miles per hour less, the trip would have taken 1 hour and 40 minutes more. Find the actual speed of the train.
I tried setting it up like this: (x/300)-([x-15]/300)=1.667
Thank you! Found 3 solutions by ikleyn, greenestamps, josgarithmetic:Answer by ikleyn(52781) (Show Source):
(1) Don't use a decimal approximation for the number of hours. Use 5/3 hours.
(2) Time is distance divided by speed -- not speed divided by distance.
(3) The greater time is at the lower speed; the the 5/3 hours difference is (time at lower speed) minus (time at higher speed). You have the two expressions in the wrong order in your equation.
So....
Multiply everything by the common denominator, x(x-15); and multiply everything by 3/5 to get rid of the fraction on the right.
That will give you the quadratic equation which you can solve by completing the square.