SOLUTION: A rock is thrown upward from a bridge that is 53 feet above a road. The rock reaches its maximum height above the road 0.61 seconds after it is thrown and contacts the road 3.25 se

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Question 1127890: A rock is thrown upward from a bridge that is 53 feet above a road. The rock reaches its maximum height above the road 0.61 seconds after it is thrown and contacts the road 3.25 seconds after it was thrown.

Write a Function (f) that determines the rock's height above the road (in feet) in terms of the number of seconds t since the rock was thrown.
f(t)=
Answer by Alan3354(69443) About Me  (Show Source):
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A rock is thrown upward from a bridge that is 53 feet above a road. The rock reaches its maximum height above the road 0.61 seconds after it is thrown and contacts the road 3.25 seconds after it was thrown.

Write a Function (f) that determines the rock's height above the road (in feet) in terms of the number of seconds t since the rock was thrown.
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Using 32 ft/sec/sec as acceleration of gravity:
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f(t) = -16t^2 + vt + 53 ---- v = speed upward at launch.