SOLUTION: the equation of the path of a cricket ball thrown is y = x - x^2/50, where x m and y m are the horizontal and vertical heights, travelled respectively. Calculate the greatest verti

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: the equation of the path of a cricket ball thrown is y = x - x^2/50, where x m and y m are the horizontal and vertical heights, travelled respectively. Calculate the greatest verti      Log On


   

Question 1125744: the equation of the path of a cricket ball thrown is y = x - x^2/50, where x m and y m are the horizontal and vertical heights, travelled respectively. Calculate the greatest vertical height reached and the horizontal distance travelled.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the equation of the path of a cricket ball thrown is y = x - x^2/50, where x m and y m are the horizontal and vertical heights, travelled respectively. Calculate the greatest vertical height reached and the horizontal distance travelled.
--------------
Is it y+=+x+-+x%5E2%2F50 ?
Or y+=+%28x+-+x%5E2%29%2F50 ?