SOLUTION: Use the model for the period of a pendulum, T, such that T = 2π sqrt (L/ g), where the length of the pendulum is L and the acceleration due to gravity is g. If the acce

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Use the model for the period of a pendulum, T, such that T = 2π sqrt (L/ g), where the length of the pendulum is L and the acceleration due to gravity is g. If the acce      Log On


   

Question 1124490: Use the model for the period of a pendulum, T, such that T = 2π sqrt (L/ g),
where the length of the pendulum is L and the acceleration due to gravity is g.
If the acceleration due to gravity is 9.8 m/s2 and the period equals 5 s, find the length to the nearest cm
(100 cm = 1 m).

*For this, I am completely lost as to both how the equation should be set up and the steps needed to solve the problem. If someone could help, it would be greatly appreciated!*
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
T = 2%2Api%2Asqrt%28L%2Fg%29  ====>  square both sides  ====>


T%5E2 = %282pi%29%5E2%2A%28L%2Fg%29


%28T%5E2%2Ag%29%2F%284%2Api%5E2%29 = L


L = %28T%5E2%2Ag%29%2F%284%2Api%5E2%29 = %285%5E2%2A9.8%29%2F%284%2A%283.14159%29%5E2%29 = 6.21 meters = 621 centimeters = 621 cm.