Question 1118597: A positive real number is 6 less than another. If the sum of the squares of the two numbers is 38, then find the numbers. Found 2 solutions by Alan3354, ikleyn:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A positive real number is 6 less than another. If the sum of the squares of the two numbers is 38, then find the numbers.
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x^2 + (x+6)^2 = 38
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Tho there is a solution, I suspect a typo.
x^2 + (x+6)^2 = 38
x^2 + x^2 + 12x + 36 = 38
2x^2 + 12x = 2
x^2 + 6x = 1
(x+3)^2 = 10
x = - 3 +/- .
Since we want a positive number, the answer is
x = -3 + sqrt(10).
The two real numbers are and .
