SOLUTION: What is the nth term rule of the quadratic sequence below? 6 , 12 , 20 , 30 , 42 , 56 , 72 , . . .

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Question 1116736: What is the nth term rule of the quadratic sequence below?
6
,
12
,
20
,
30
,
42
,
56
,
72
,
.
.
.

Found 2 solutions by ikleyn, Edwin McCravy:
Answer by ikleyn(52778) About Me  (Show Source):
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
The good lady mistakenly thought it was an arithmetic 
sequence, but it is a quadratic sequence, so we assume:

matrix%281%2C3%2C%0D%0A%0D%0Aa%5Bn%5D%2C%22%22=%22%22%2CAn%5E2%2BBn%2BC%29

[Don't confuse the capital A with the subscripted small an,
for the nth term.  They are different.]

There are 3 unknowns A,B, and C, so we need 3 equations,
so we only need the first 3 terms, with n=1,2,3.

a%5B1%5D=6, a%5B2%5D=12, a%5B3%5D=20

Substitute n=1:

matrix%281%2C3%2C%0D%0A%0D%0Aa%5B1%5D%2C%22%22=%22%22%2CA%281%29%5E2%2BB%281%29%2BC%29

matrix%281%2C3%2C%0D%0A%0D%0A6%2C%22%22=%22%22%2CA%2BB%2BC%29

So the first equation is A%2BB%2BC=6

Substitute n=2:

matrix%281%2C3%2C%0D%0A%0D%0Aa%5B2%5D%2C%22%22=%22%22%2CA%282%29%5E2%2BB%282%29%2BC%29

matrix%281%2C3%2C%0D%0A%0D%0A12%2C%22%22=%22%22%2C4A%2B2B%2BC%29

So the second equation is 4A%2B2B%2BC=12

Substitute n=3:

matrix%281%2C3%2C%0D%0A%0D%0Aa%5B3%5D%2C%22%22=%22%22%2CA%283%29%5E2%2BB%283%29%2BC%29

matrix%281%2C3%2C%0D%0A%0D%0A20%2C%22%22=%22%22%2C9A%2B3B%2BC%29

So the third equation is 9A%2B3B%2BC=20

We have this 3×3 system:

system%28A%2BB%2BC=6%2C4A%2B2B%2BC=12%2C9A%2B3B%2BC=20%29

Subtract the first equation from the second:

3A%2BB=6

Subtract the second equation from the third equation:

5A%2BB=8

So we have this 2×2 system:

system%283A%2BB=6%2C5A%2BB=8%29

Subtract the first equation from the second:

2A=2

A=1

Substitute in

3A%2BB=6
3%281%29%2BB=6
3%2BB=6
B=3

Substitute in 

A%2BB%2BC=6
1%2B3%2BC=6
4%2BC=6
C=2

We substitute in the expression for the nth term 

matrix%281%2C3%2C%0D%0A%0D%0Aa%5Bn%5D%2C%22%22=%22%22%2CAn%5E2%2BBn%2BC%29


matrix%281%2C3%2C%0D%0A%0D%0Aa%5Bn%5D%2C%22%22=%22%22%2C1n%5E2%2B3n%2B2%29

matrix%281%2C3%2C%0D%0A%0D%0Aa%5Bn%5D%2C%22%22=%22%22%2Cn%5E2%2B3n%2B2%29    

If you like you can factor that as

matrix%281%2C3%2C%0D%0A%0D%0Aa%5Bn%5D%2C%22%22=%22%22%2C%28n%2B1%29%28n%2B2%29%29    

Checking to make sure it works for n=1,...,7 with the given sequence:

 
 
 
 
 
 
 

Edwin