SOLUTION: Will you please help me solve the following quadratic equation? m=(m[0])/sqrt(1-(v^2/c^2)) solving for c This is what I've attempted... multiply both sides by the LCM sqrt1

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Question 111604: Will you please help me solve the following quadratic equation?
m=(m[0])/sqrt(1-(v^2/c^2)) solving for c
This is what I've attempted...
multiply both sides by the LCM sqrt1-(v^2/c^2)to get rid of the fraction
(m)qrt1-(v^2/c^2)=m[0]
then multiply both sides again to get rid of the fraction in the sqrt?
(mc^2)sqrtc^2-v^2=m[0]
then divide both sides by (m)sqrt(c^2-v^2)
c^2=(m[0])/(m)sqrt(c^2-v^2)
square both sides with a final answer of
c=sqrt(m[0])/(m)sqrt(c^2-v^2)
Thank you in advance for your help!!
Brenda

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
m=(m[0])/sqrt(1-(v^2/c^2)) solving for c
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Interchange m and [sqrt(1-(v^2/c^2)) to get:
sqrt(1-(v^2/c^2)) = m[0]/m
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Square both sides to get
1-(v^2/c^2) = [m[0]/m]^2
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Then v^2/c^2 = 1-[m(0]/m]^2
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And c^2 == v^2/[1-[m[0]/m]^2]
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Take the sqrt to find "c".
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Cheers,
Stan H.