SOLUTION: The coin is in the shape of a circle of radius 3 cm with a square of sides x cm removed from its centre. The area of each face of the coin is 7pi cm^2.
i) form an equation in x a
Question 1113073: The coin is in the shape of a circle of radius 3 cm with a square of sides x cm removed from its centre. The area of each face of the coin is 7pi cm^2.
i) form an equation in x and show that it reduces to 2pi-x^2=0.
ii) solve the equation 2pi-x^2=0.
iii) find the perimeter of the square Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The coin is in the shape of a circle of radius 3 cm with a square of sides x cm removed from its centre.
The area of each face of the coin is 7pi cm^2.
i) form an equation in x and show that it reduces to 2pi-x^2=0. = = = 0
:
ii) solve the equation 2pi-x^2=0.
x =
:
iii) find the perimeter of the square
p =
