SOLUTION: Ok this is my 4th and final question of the day. you guys are awesome to spend your time helping non math minded people like myself:) solve the equation: x+6/3=x+6/x

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Question 111206This question is from textbook university of Phoenix Elementary and Intermediate Algebra
: Ok this is my 4th and final question of the day. you guys are awesome to spend your time helping non math minded people like myself:)
solve the equation:
x+6/3=x+6/x This question is from textbook university of Phoenix Elementary and Intermediate Algebra

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
I'm not sure whether you meant: x%2B%286%2F3%29=x%2B%286%2Fx%29 or %28x%2B6%29%2F3=%28x%2B6%29%2Fx.
:
x%2B%286%2F3%29=x%2B%286%2Fx%29
x%2B2-x=x-x%2B%286%2Fx%29
2=6%2Fx
12=1%2Fx
x=1%2F12
:
Or if you meant the second way:
:
%28x%2B6%29%2F3=%28x%2B6%29%2Fx. For this you need to remember the following rule:
if p%2Fq=r%2Fs, then ps=rq. In this case:
x%28x%2B6%29=3%28x%2B6%29
x%5E2%2B6x=3x%2B18
x%5E2%2B3x-18=0
%28x%2B6%29%28x-3%29=0
Hence:
x=-6 or x=3
Both of which are in the domain of the function, since the only real number excluded from the domain is 0 -- the right side of the equation would be undefined for x = 0.
:
To avoid confusion next time, use parentheses, like this: (x+6)/3=(x+6)/x