SOLUTION: Can anyone help me with this? 5x^2+3x+5=0

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Question 110340: Can anyone help me with this?

5x^2+3x+5=0
Found 2 solutions by scott8148, jim_thompson5910:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
this does not factor ... use the quadratic formula to find solutions

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic


ax%5E2%2Bbx%2Bc=0


the general solution using the quadratic equation is:


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29




So lets solve 5%2Ax%5E2%2B3%2Ax%2B5=0 ( notice a=5, b=3, and c=5)





x+=+%28-3+%2B-+sqrt%28+%283%29%5E2-4%2A5%2A5+%29%29%2F%282%2A5%29 Plug in a=5, b=3, and c=5




x+=+%28-3+%2B-+sqrt%28+9-4%2A5%2A5+%29%29%2F%282%2A5%29 Square 3 to get 9




x+=+%28-3+%2B-+sqrt%28+9%2B-100+%29%29%2F%282%2A5%29 Multiply -4%2A5%2A5 to get -100




x+=+%28-3+%2B-+sqrt%28+-91+%29%29%2F%282%2A5%29 Combine like terms in the radicand (everything under the square root)




x+=+%28-3+%2B-+i%2Asqrt%2891%29%29%2F%282%2A5%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




x+=+%28-3+%2B-+i%2Asqrt%2891%29%29%2F%2810%29 Multiply 2 and 5 to get 10




After simplifying, the quadratic has roots of


x=-3%2F10%2Bsqrt%2891%29%2F10%2Ai or x=-3%2F10-sqrt%2891%29%2F10%2Ai