SOLUTION: I am lost on this one. A wire is stretched from the ground to the top of an antenna tower. The wire is 30 feet long. The height of the tower is 6 ft greater than the distance

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I am lost on this one. A wire is stretched from the ground to the top of an antenna tower. The wire is 30 feet long. The height of the tower is 6 ft greater than the distance       Log On


   

Question 1100274: I am lost on this one.
A wire is stretched from the ground to the top of an antenna tower. The wire is 30 feet long. The height of the tower is 6 ft greater than the distance d from the tower’s base to the end of the wire. Find the distance d and the height of the tower.
Any help would be appreciated!
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A wire is stretched from the ground to the top of an antenna tower. The wire is 30 feet long. The height of the tower is 6 ft greater than the distance d from the tower’s base to the end of the wire. Find the distance d and the height of the tower.
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It's a right triangle.
d^2 + (d+6)^2 = 30^2