SOLUTION: How do you convert to turning point form for this equation: 2x^2 - 5x -1 Thanks

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Question 1100152: How do you convert to turning point form for this equation: 2x^2 - 5x -1
Thanks
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Expression, 2x%5E2+-+5x+-1

EQUATION, y=2x%5E2-5x-1%29


"turning point"?
VERTEX?

2%28x%5E2-5x%2F2%29-1
2%28x%5E2-5x%2F2%2B%285%2F4%29%5E2-%285%2F4%29%5E2%29-1
2%28x%5E2-5%2F4%29%5E2-2%285%2F4%29%5E2-1
2%28x-5%2F4%29%5E2-%282%2A5%2A5%29%2F%282%2A2%2A2%2A2%29-1
2%28x-5%2F4%29%5E2-25%2F8-8%2F8
2%28x-5%2F4%29%5E2-33%2F8
2%28x-5%2F4%29%5E2-4%261%2F8

Vertex is at ( 1.25, -4.125 ) or ( -5/4, -33/8 ).

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
This conversion operation is called "completing the squares".

If you want to learn about this procedure, see the lessons
    - HOW TO complete the square - Learning by examples
in this site.


Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this textbook under the topic "Quadratic equations".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.