SOLUTION: Solve 4x^2=13x+12

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Question 109854: Solve 4x^2=13x+12
Found 2 solutions by stanbon, Fombitz:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve 4x^2=13x+12
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4x^2-13x-12 = 0
x = [13 +- sqrt(169-4*4*-12)]/8
x = [13 +- sqrt(361)]/8
x = [13 +- 19]/8
x = 4 or x = -3/4
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Cheers,
Stan H.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2=13x%2B12
4x%5E2-13x-12=0
x%5E2-%2813%2F4%29x-3=0
%28x-4%29%28x%2B3%2F4%29=0
x=4 and x=-.75
Check your solutions.
4x%5E2=13x%2B12
4%284%29%5E2=13%284%29%2B12
64=52%2B12
64=64
True statement
4%28-3%2F4%29%5E2=13%28-3%2F4%29%2B12
9%2F4=-39%2F4%2B48%2F4
9=-39%2B48
9=9
True statement.
Good answers.