SOLUTION: Suppose the decimal 0.28 is equal to {1}/{n}+{2}/{n^2}, where n is negative. Find n.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Suppose the decimal 0.28 is equal to {1}/{n}+{2}/{n^2}, where n is negative. Find n.      Log On


   

Question 1096608: Suppose the decimal 0.28 is equal to {1}/{n}+{2}/{n^2}, where n is negative. Find n.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


1%2Fn+%2B+2%2Fn%5E2+=+0.28+=+28%2F100+=+7%2F25

Clear fractions by multiplying by the LCD, which is 25n^2:
25n+%2B+50+=+7n%5E2
7n%5E2-25n-50+=+0
%287n%2B10%29%28n-5%29+=+0

n = -10/7 or n = 5; since the problem asks for the negative value, the answer is -10/7.