SOLUTION: Find the (x,y) coordinate of the maximum or minimum value of the following quadratic equation:-1/6x^2-1/3x+8=y

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the (x,y) coordinate of the maximum or minimum value of the following quadratic equation:-1/6x^2-1/3x+8=y      Log On


   

Question 1094691: Find the (x,y) coordinate of the maximum or minimum value
of the following quadratic equation:-1/6x^2-1/3x+8=y
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+y+=+%28-1%2F6%29%2Ax%5E2+-+%281%2F3%29%2Ax+%2B+8+
The x-value of the vertex
( maximum or minimum ) is at:
+-b%2F%282a%29+
+a+=+-1%2F6+
+b+=+-1%2F3+
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+-b%2F%282a%29+=+%281%2F3%29+%2F+%28+-1%2F3%29+
+x%5Bv%5D+=+-1+
plug this value back into equation
+y%5Bv%5D+=+%28-1%2F6%29%2A%28-1%29%5E2+-+%281%2F3%29%2A%28-1%29+%2B+8+
+y%5Bv%5D+=+-1%2F6+%2B+1%2F3+%2B+8+
+y%5Bv%5D+=+1%2F6+%2B+48%2F6+
+y%5Bv%5D+=+49%2F6+
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The vertex is at ( -1, 49/6 )
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Here's the plot: