SOLUTION: solve the following quadratic equation x(x-3)(x+3) = 0 answer is x =0, x=3, x=-3 but I have no idea how to caulculate

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: solve the following quadratic equation x(x-3)(x+3) = 0 answer is x =0, x=3, x=-3 but I have no idea how to caulculate      Log On


   

Question 1091188: solve the following quadratic equation
x(x-3)(x+3) = 0
answer is x =0, x=3, x=-3 but I have no idea how to caulculate
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

x%28x-3%29%28x%2B3%29+=+0-> here, you are given zero product (remember zero product theorem, easier way to find zeros)
so, the product of three numbers x, %28x-3%29, and %28x%2B3%29 will be equal to 0 if at least one of them is equal to zero
it means
if x+=+0
or, if %28x-3%29+=+0-> this one is equal to zero if x=3
or, if %28x%2B3%29+=+0-> this one is equal to zero if x=-3
so, your answer is:
+x+=0, x=3, x=-3