SOLUTION: Sketch the graph of the function below. Please plot at least 5 points and show the complete solution. f(b)=-b^2-2b+3

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Sketch the graph of the function below. Please plot at least 5 points and show the complete solution. f(b)=-b^2-2b+3      Log On


   

Question 1090823: Sketch the graph of the function below. Please plot at least 5 points and show the complete solution.
f(b)=-b^2-2b+3
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
f%28b%29=-b%5E2-2b%2B3

choose values for b, calculate f%28b%29(same as f%28x%29 or y), and make table
b|f%28b%29
-5|-12 ->f%28-5%29=+-%28-5%29%5E2-2%28-5%29%2B3=-25%2B10%2B3=-12
-2|3 ->f%28-2%29=+-%28-2%29%5E2-2%28-2%29%2B3=-4%2B4%2B3=3
-1|4 ->f%28-1%29=+-%28-1%29%5E2-2%28-1%29%2B3=-1%2B2%2B3=4
0|3 ->f%280%29=+-%280%29%5E2-2%280%29%2B3=3
1|0 ->f%281%29=+-%281%29%5E2-2%281%29%2B3=-1-2%2B3=0
2|-5 ->f%282%29=+-%282%29%5E2-2%282%29%2B3=-4-4%2B3=-5
3|-12 ->f%283%29=+-%283%29%5E2-2%283%29%2B3=-9-6%2B3=-15%2B3=-12
plot these points and draw a line: