SOLUTION: If an object is thrown/launched into the air, the following formula can be used to model it's path.
y equal left parenthesis v over u right parenthesis x plus left parenthes
Question 1088645: If an object is thrown/launched into the air, the following formula can be used to model it's path.
y equal left parenthesis v over u right parenthesis x plus left parenthesis fraction numerator g over denominator 2 u to the power of 2 end fraction right parenthesis x to the power of 2
where
y is the object's vertical distance (in feet) above from where it was thrown
x is the object's horizontal distance (in feet) away from where it was thrown
and
u is the objects' initial horizontal velocity
v is the object's initial vertical velocity
g is the force exerted by gravity.
Suppose a ball is launched from ground level (on level ground) with an initial horizontal velocity of 50 feet/second and an initial vertical velocity of 100 feet/second and that the force due to gravity was -32 feet/second2
a) Substitute those values into the given formula and simplify.
b) Find how far the ball is away when the ball hits the ground again. Show the equation you solved and tell or show how you solved it.
You can put this solution on YOUR website! If an object is thrown/launched into the air, the following formula can be used to model it's path.
y equal left parenthesis v over u right parenthesis x plus left parenthesis fraction numerator g over denominator 2 u to the power of 2 end fraction right parenthesis x to the power of 2
where
y is the object's vertical distance (in feet) above from where it was thrown
x is the object's horizontal distance (in feet) away from where it was thrown
and
u is the objects' initial horizontal velocity
v is the object's initial vertical velocity
g is the force exerted by gravity.
Suppose a ball is launched from ground level (on level ground) with an initial horizontal velocity of 50 feet/second and an initial vertical velocity of 100 feet/second and that the force due to gravity was -32 feet/second2
a) Substitute those values into the given formula and simplify.
do the math
y = 2x - .0064x^2
b) Find how far the ball is away when the ball hits the ground again. Show the equation you solved and tell or show how you solved it.
when is hits the ground y=0
-.0064x^2 + 2x = 0
divide both sides by x
-.0064x + 2 = 0
-.0064x = -2
x =
x = +312.5 ft
