SOLUTION: Find the values of n when x^2 − 3x − n = 0 has two solutions.

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Question 1088370: Find the values of n when x^2 − 3x − n = 0 has two solutions.
Found 2 solutions by htmentor, Alan3354:
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
In order for there to be two solutions, the discriminant b^2 - 4ac has to be greater than 0.
So we have (-3)^2 - 4(1)(-n) > 0
9 > -4n
-9/4 < n
n > -9/4
So n must be greater than -9/4

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the values of n when x^2 - 3x - n = 0 has two solutions.
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All quadratics have 2 solutions --> n is any real number.
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Disc = b^2 - 4ac
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Disc > 0 --> 2 distinct real solutions
Disc = 0 --> 2 equal real solutions.
Disc < 0 --> 2 complex solutions.
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All cubics have 3 solutions.
All quartics (4th power) have 4 solutions.
etc