SOLUTION: The weight of an object varies inversely with the square of the distance to the center of the Earth. At sea level (6,400 kilometers from the Earth's center) an astronaut weighs 100

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The weight of an object varies inversely with the square of the distance to the center of the Earth. At sea level (6,400 kilometers from the Earth's center) an astronaut weighs 100      Log On


   

Question 1087264: The weight of an object varies inversely with the square of the distance to the center of the Earth. At sea level (6,400 kilometers from the Earth's center) an astronaut weighs 100 kilos. Calculate the weight of the astronaut on a space vehicle located at 200 kilometers from the earth's surface.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
W=k%2FD%5E2
100=k%2F6400%5E2
k=%286400%29%5E2%28100%29
So then,
W%5B200%5D=k%2F%28%286400%2B200%29%5E2%29
W%5B200%5D=%28%286400%29%5E2%28100%29%29%2F%286600%29%5E2
W%5B200%5D=%2864%2F66%29%5E2%2A100
W%5B200%5D=%2832%2F33%29%5E2%28100%29
Work that out for the answer in kg.