SOLUTION: First multiply by 4 then complete the square. {{{4(x^2-5x+3)=4x^2-20x+12=0}}}

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: First multiply by 4 then complete the square. {{{4(x^2-5x+3)=4x^2-20x+12=0}}}      Log On


   

Question 1086777: First multiply by 4 then complete the square.
4%28x%5E2-5x%2B3%29=4x%5E2-20x%2B12=0
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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First multiply by 4 then complete the square.
4%28x%5E2-5x%2B3%29=4x%5E2-20x%2B12=0
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More sensible to complete the square, form your expression inside the grouping, and after that to multiply by the 4.

4%28x%5E2-5x%2B3%2B%285%2F2%29%5E2-%285%2F2%29%5E2%29

4%28x%5E2-5x%2B%285%2F2%29%5E2%2B3-%285%2F2%29%5E2%29

4%28%28x-5%2F2%29%5E2%2B3-25%2F4%29

4%28x-5%2F2%29%5E2-13=0
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