SOLUTION: Find all pairs of real numbers (x,y) such that x + y = 6 and x^2 + y^2 = 28. If you find more than one pair, then list your pairs in order by increasing x value, separated by comma

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find all pairs of real numbers (x,y) such that x + y = 6 and x^2 + y^2 = 28. If you find more than one pair, then list your pairs in order by increasing x value, separated by comma      Log On


   

Question 1085964: Find all pairs of real numbers (x,y) such that x + y = 6 and x^2 + y^2 = 28. If you find more than one pair, then list your pairs in order by increasing x value, separated by commas. For example, to enter the solutions (2,4) and (-3,9), you would enter "(-3,9),(2,4)" (without the quotation marks).
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2B%286-x%29%5E2=28

x%5E2%2B36-12x%2Bx%5E2-28=0

2x%5E2-12x%2B8=0

x%5E2-6x%2B4=0

x=%286%2B-+sqrt%2836-4%2A4%29%29%2F2

x=%286%2B-+sqrt%2820%29%29%2F2
x=%286%2B-+2%2Asqrt%285%29%29%2F2
highlight%28x=3%2B-+sqrt%285%29%29


You can find each corresponding y coordinate from y=6-x.