SOLUTION: https://cedu-spw-p06.austin.utexas.edu/canvas-files/ALG-1B-66502/unit07/lsn04/U07L04EvGA9.pdf I'm having trouble please help me

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: https://cedu-spw-p06.austin.utexas.edu/canvas-files/ALG-1B-66502/unit07/lsn04/U07L04EvGA9.pdf I'm having trouble please help me      Log On


   

Question 1085926: https://cedu-spw-p06.austin.utexas.edu/canvas-files/ALG-1B-66502/unit07/lsn04/U07L04EvGA9.pdf
I'm having trouble please help me
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

1)
Given the vertex form of this quadratic equation complete the following tasks:
f%28x%29=%28x%2B3%29%5E2-2
a)
If f%28x%29 is shifted three units to the right, shifted up two units, and reflected vertically over the x-axis, what is the new function?
Shifting to the right works the same way; f+%28x+-+b%29 is f%28x%29 shifted b+units to the right.
given b=3
f%28x%29=%28x%2B3-3%29%5E2-2
f%28x%29=x%5E2-2
to move a function up, you add outside the function: f+%28x%29+%2B+b is f+%28x%29 moved up b units.
b=2
f%28x%29=x%5E2-2%2B2
f%28x%29=x%5E2
and reflected vertically over the x-axis: f%28x%29=-f%28x%29
f%28x%29=-x%5E2-> your new function


+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%28x%2B3%29%5E2-2%2C+-x%5E2%29+