SOLUTION: Which function's graph has a vertex at (-3,-4)and contains the point (-6,-7)? A. y=-1/3(x+3)^2-4 B. y=-1/3(x-3)^2-4 C. y=-3(x-3)^2-4 D. y=-3(x+3)^2-4

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Which function's graph has a vertex at (-3,-4)and contains the point (-6,-7)? A. y=-1/3(x+3)^2-4 B. y=-1/3(x-3)^2-4 C. y=-3(x-3)^2-4 D. y=-3(x+3)^2-4      Log On


   

Question 1084015: Which function's graph has a vertex at (-3,-4)and contains the point (-6,-7)?
A. y=-1/3(x+3)^2-4
B. y=-1/3(x-3)^2-4
C. y=-3(x-3)^2-4
D. y=-3(x+3)^2-4
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Which function's graph has a vertex at (-3,-4)and contains the point (-6,-7)?
use vertex formula y=a%28x-h%29%5E2%2Bk where h and k are coordinates of the vertex
A.
y=-%281%2F3%29%28x%2B3%29%5E2-4...-> h=-3 and k=-4; so, this function has a vertex at (-3,-4)
now check the point (-6,-7)
-7=-%281%2F3%29%28-6%2B3%29%5E2-4
-7=-%281%2F3%29%28-3%29%5E2-4
-7=-%281%2Fcross%283%29%29cross%289%293-4
-7=-3-4
-7=-7-> since true, this is your answer


no need to check other options
B.
y=-%281%2F3%29%28x-3%29%5E2-4-> not answer
C. y=-3%28x-3%29%5E2-4-> not answer
D. y=-3%28x%2B3%29%5E2-4-> not answer