SOLUTION: the function f (x) = -0.002x^2 +0.66x models the path of a softball that is hit for a homerun, where f(x) given the height of the ball and x gives the distance from where it was h

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: the function f (x) = -0.002x^2 +0.66x models the path of a softball that is hit for a homerun, where f(x) given the height of the ball and x gives the distance from where it was h      Log On


   



Question 1082453: the function f (x) = -0.002x^2 +0.66x models the path of a softball that is hit for a homerun, where f(x) given the height of the ball and x gives the distance from where it was hit in feet.
How far does the ball travel before hitting the ground?
How high does the ball go?

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


When the ball hits the ground, the value of the function is zero, because zero is the height of the ground.

Set the function equal to zero and solve the quadratic equation. One of your roots will be zero since this is a very poor model of the real world situation. This model assumes that the ball was hit when it was touching the ground. So your answer to the first question is the non-zero root of the equation.

There are two ways to answer the second question. Use algebra to find the coordinate of the vertex of the parabola or use calculus and take the first derivative, set it equal to zero, and solve. Either way, find the value of the function at the vertex.

John

My calculator said it, I believe it, that settles it