SOLUTION: Find three consecutive integers such that the square of the first plus the product of the other two is 46

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Question 1077902: Find three consecutive integers such that the square of the first plus the product of the other two is 46
Answer by josgarithmetic(39617) About Me  (Show Source):
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Integers are n, n+1, n+2.

n%5E2%2B%28n%2B1%29%28n%2B2%29=46

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n%5E2%2Bn%5E2%2B3n%2B2=46
2n%5E2%2B3n-44=0
%282n%2B11%29%28n-4%29=0

highlight%28n=4%29

The integers are 4, 5, 6.