SOLUTION: The distance a person falls on a bungee chord in metres, h may be modelled with time, t in seconds according to: h=2(t-5)^2-50 What is the greatest distance a person will reach

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Question 1077585: The distance a person falls on a bungee chord in metres, h may be modelled with time, t in seconds according to:
h=2(t-5)^2-50
What is the greatest distance a person will reach on the bungee chord from their starting position?
Answer by MathLover1(20849) About Me  (Show Source):
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The distance a person falls on a bungee chord in meters, h may be modeled with time, t in seconds according to:
h=2%28t-5%29%5E2-50+
What is the greatest distance a person will reach on the bungee chord from their starting position?
recall: The maximum distance the bungee jumper falls corresponds to the lowest point in the fall.
in your case, h=2%28t-5%29%5E2-50+, we have an upside-down parabola because the leading coefficient is negative, and its lowest point is h%5B1%5D%2Ck+ (I put h%5B1%5D to make it different from distance h) which is its vertex
equation in vertex form h=a%28t-h%5B1%5D%29%5E2%2Bk+
h=2%28t-5%29%5E2-50+ since you are given in vertex form, you see that h%5B1%5D=5 and k=-50
so, the vertex is at (5,-50) and the greatest distance a person will reach on the bungee chord from their starting position is h=-50