SOLUTION: A football is kicked at 40 yards away from a goal post that is 10 feet high. Its path is modeled by y = -0.03x^2 + 1.6x, where x is the horizontal distance in yards traveled by the
Question 1077361: A football is kicked at 40 yards away from a goal post that is 10 feet high. Its path is modeled by y = -0.03x^2 + 1.6x, where x is the horizontal distance in yards traveled by the football and y is the corresponding height above the ground in feet.
Does the football go over the goal post? How far above or below the goal post is the football? Use two or more complete sentences to explain your answers. (Hint: The unit conversion is built into the given function.) Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A football is kicked at 40 yards away from a goal post that is 10 feet high.
Its path is modeled by y = -0.03x^2 + 1.6x, where x is the horizontal distance in yards traveled by the football and y is the corresponding height above the ground in feet.
Does the football go over the goal post?
How far above or below the goal post is the football?
:
Solve for y when x = 40 yds
y = -.03(40^2) + 1.6(40)
y = -48 + 64
y = 16 ft at 40yds, so it will clear the goal bar by 6 ft
:
Graphically, green line is 10ft
