SOLUTION: Draw a rough sketch of the quadradic function. Label the vertex and any x and y intercepts. f(x)=-2(x-3)2+8 (that is (x-3) squared)

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Draw a rough sketch of the quadradic function. Label the vertex and any x and y intercepts. f(x)=-2(x-3)2+8 (that is (x-3) squared)      Log On


   

Question 107171: Draw a rough sketch of the quadradic function. Label the vertex and any x and y intercepts.
f(x)=-2(x-3)2+8 (that is (x-3) squared)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Draw a rough sketch of the quadratic function. Label the vertex and any x and y intercepts.
f(x)=-2(x-3)^2+8
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Notice that f(3) is 8.
That is the vertex.
Notice that -2(x-3)^2 is always negative for all values of x
so the parabola opens down from the vertex.
Notice that when x=0, y = 2*9+8 = 26; that is the y-intercept.
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graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C-2%28x-3%29%5E2%2B8%29
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Cheers,
Stan H.