SOLUTION: find the value of the discriminant and determine the number of real solutions for the quadratic equation 30𝑦2 − 60𝑦 + 300 = 5𝑦2 + 120𝑦 &#872

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: find the value of the discriminant and determine the number of real solutions for the quadratic equation 30𝑦2 − 60𝑦 + 300 = 5𝑦2 + 120𝑦 &#872      Log On


   



Question 1068983: find the value of the discriminant and determine the number of real solutions for the quadratic equation 30𝑦2 − 60𝑦 + 300 = 5𝑦2 + 120𝑦 − 24.


Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
.
Your first step is to move all the terms from the right side to the left side with the opposite signs.


Your second step is to simplify the obtained equation (to combine like terms) to get the quadratic equation in a standard form


ax%5E2+%2B+bx+%2B+c = 0.


Your third step is to calculate the discriminant d = (((b^2 - 4ac}}}.


    If the discriminant is positive number, then the equation has TWO real solutions.

    If the discriminant is positive number, then the equation has ONLY ONE real solution.

    If the discriminant is negative number, then the equation has NO real solutions.



See the lessons 

    - Introduction into Quadratic Equations

    - PROOF of quadratic formula by completing the square

in this site.