SOLUTION: 1. Find two integers whose product is 14 such that one of the integers is three less than five times the other integer. 2. The perimeter of a rectangle is 50 inches, and the ar

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 1. Find two integers whose product is 14 such that one of the integers is three less than five times the other integer. 2. The perimeter of a rectangle is 50 inches, and the ar      Log On


   

Question 1065940: 1. Find two integers whose product is 14 such that one of the integers is three less than five times the other integer.
2. The perimeter of a rectangle is 50 inches, and the area is 136 square inches. Find the length and width of the rectangle.
3. The combined area of a square and a rectangle is 124 square centimeters. The width of the rectangle is 4 centimeters more than the length of a side of the square, and the length of the rectangle is 2 centimeters more than its width. Find the dimensions of the square and the rectangle.
4. 9x3 + x2 + 7 from 5x3 − x − 8

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Doing #3 only

x, the side length of the square
x+4 is the width for the rectangle, and 2+(x+4) is the length of the rectangle.

Combined Area:
x%5E2%2B%28x%2B4%29%28x%2B6%29=124

STEPS
x%5E2%2Bx%5E2%2B10x%2B24=124
2x%5E2%2B10x-100=0
x%5E2%2B5x-50=0
%28x-5%29%28x%2B10%29=0
This will mean that highlight%28x=5%29, side length of the square.

Evaluate the rectangle's x+4 and x+6.