SOLUTION: Solve the following equation by first doing a substitution to make it a quadratic. (x+7)^2 + 5(x+7) -50=0

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Solve the following equation by first doing a substitution to make it a quadratic. (x+7)^2 + 5(x+7) -50=0      Log On


   

Question 1061503: Solve the following equation by first doing a substitution to make it a quadratic.
(x+7)^2 + 5(x+7) -50=0
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I could say:
+x+%2B+7+=+z+
then:
+z%5E2+%2B+5z+-+50+=+0+
By looking at this I see:
+%28+z+%2B+10+%29%2A%28+z+-+5+%29+=+0+
+z+=+-10+
+z+=+5+
and
+x+%2B+7+=+z+
+x+%2B+7+=+-10+
+x+=+-17+
and
+x+%2B+7+=+5+
+x+=+-2+
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Here's the plot: