SOLUTION: the width of a rectangle is 6 ft less than the length. the area is 10 ft^2. find the length and the width

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: the width of a rectangle is 6 ft less than the length. the area is 10 ft^2. find the length and the width      Log On


   

Question 1061237: the width of a rectangle is 6 ft less than the length. the area is 10 ft^2. find the length and the width
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
x for length
x-6 for width

x%28x-6%29=10

x%5E2-6x-10=0
Discriminant is %28-6%29%5E2-4%2A1%2A%28-10%29=36%2B40=76.
Discriminant is 4%2A19.

x=%286%2B-+2%2Asqrt%2819%29%29%2F2

highlight%28x=3%2Bsqrt%2819%29%29, only the PLUS form must be chosen.

x-6=3-6%2Bsqrt%2819%29
highlight%28x-6=sqrt%2819%29-3%29