Question 1058530: If an object is thrown downward with an initial velocity of v0, then the distance it travels is given by s=4.9t^2 + v0t. An object is thrown downward from a cliff 500 m high and it travels 183.5 m in 3 sec. What was the initial velocity of the object?
Answer by ikleyn(52778)   (Show Source):
You can put this solution on YOUR website! .
If an object is thrown downward with an initial velocity of v0, then the distance it travels is given by s=4.9t^2 + v0t.
An object is thrown downward from a cliff 500 m high and it travels 183.5 m in 3 sec. What was the initial velocity of the object?
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If you just have read the condition, then you should be able to write and to understand this equation
183.5 = 4.9*3^2 + v0*3.
In this equation everything is given and known to you, except the value of the variable v0, which is the velocity under the question.
So, all you need to do is to solve this equation for v0.
It is very simple linear equation for one unknown,
and I am sure you easily can solve it.
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